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The load considered is RL load with the impedance phase angle ϕ . Moreover, there are four diodes, D 1 –D 4 , which are employed to provide the paths for the load current driven by the stored energy in the load inductor. The period of a cycle is denoted by T . When either the switch pair (Q 1 , Q 4 ) or (Q 2 , Q 3 ) is turned on, the load voltage v o and the load current i o have the same polarity, which means the DC source provides the power to the load. On the other hand, when either the diode pair (D 1 , D 4 ) or (D 2 , D 3 ) is turned on, the load voltage v o and the load current i o have opposite polarity, which indicates the load feeds back the power to the DC side. Single Phase Half Bridge Inverter Explained. Working Principle of Single-Phase Half Bridge Inverter: As soon as i g1 is removed at t= T/2, thyristor T1 gets turned OFF. It may be seen from the waveform of gating signal that at t=T/2, i g2 is applied and hence, thyristor T2 gets turned ON. Thus, load gets directly connected to the source (V s /2) on the lower arm. Note that the polarity of voltage source on the upper & lower arm are opposite to each other. Therefore, during the time (T/2)s /2) as shown in the output voltage waveform. If the load is purely resistive, there is no need to put diode D1 & D2 as the output voltage and current are always in phase. But unfortunately, for loads other than purely resistive, the load current (i o ) will not be in phase with the load voltage (v o ). For such case, the diode connected in anti-parallel with the thyristor will allow the current to flow when main thyristor is turned off.
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